If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2=282.24
We move all terms to the left:
4x^2-(282.24)=0
We add all the numbers together, and all the variables
4x^2-282.24=0
a = 4; b = 0; c = -282.24;
Δ = b2-4ac
Δ = 02-4·4·(-282.24)
Δ = 4515.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4515.84}}{2*4}=\frac{0-\sqrt{4515.84}}{8} =-\frac{\sqrt{}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4515.84}}{2*4}=\frac{0+\sqrt{4515.84}}{8} =\frac{\sqrt{}}{8} $
| 8+10p=-6p+40 | | -3u+7=4(u-7) | | J-9=8j+40 | | 2-z=-10 | | -3(w-8)=-9w-24 | | 4x^2-48x+1=0 | | 3x-4=-19* | | 4-2m=7m+40 | | 4u-7=0 | | 6y-8=2y+12 | | 2x+19=x-55 | | 2x/2=5(2) | | 2x×19=x-55 | | 5-2y=8+4y | | 7y+7(y-6)=-28 | | 2x+19=x+55 | | 5m+15=2m+24 | | 4(x+5)-7x=17 | | (X•32)+30=(x•58)+44 | | 20x-240=0 | | 8c2+7c=1 | | 7x-4+4x+73=180 | | 14x-3=28 | | 14y2=-2y+16 | | 10+.45x=5+.65 | | 10+.45x=5+.4 | | 2=2w−10 | | 9m=66 | | t3+ 9=13 | | .15=4.3n-2.1(n-4) | | 165+u=91 | | 4=(s-46)÷8 |